View these slides online at www.Kozhukhov.co.uk/
$\langle \Delta r^2(t) \rangle = v_0^2t^2 + 2dDt; \quad t << \tau_r$
$\langle \Delta r^2(t) \rangle = 2dD_\mathrm{eff}t; \quad t >> \tau_r$
View these slides online at www.Kozhukhov.co.uk/